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20m^2-17m+3=0
a = 20; b = -17; c = +3;
Δ = b2-4ac
Δ = -172-4·20·3
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-7}{2*20}=\frac{10}{40} =1/4 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+7}{2*20}=\frac{24}{40} =3/5 $
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